scripting help

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msunrise
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scripting help

Postby msunrise » 31 Jul 2012 01:28

I have a program that allows me to generate an "openfile" button. I am trying to figure out the path to open an rtsp stream with one push of a button. I know how to make the VLC player play the rtsp stream. How do i put it all together in a path I can direct the open filer script to work.

I can get this far.

C:\Program Files (x86)\VideoLAN\VLC

I need the part that tells it to go to the url (open network stream/rtsp://xxx.dyndns.org:rtspport/x)

Anyone with a bigger brain than me please help. :D

edwardw
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VLC version: 3.0.0-git

Re: scripting help

Postby edwardw » 02 Aug 2012 16:15

Code: Select all

C:\Program Files (x86)\VideoLAN\VLC\vlc.exe rtsp://xxx.dyndns.org:rtspport/x

msunrise
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Joined: 31 Jul 2012 01:18

Re: scripting help

Postby msunrise » 03 Aug 2012 23:09

Thanks for the help.
    The first half is obvious and the url is obvious. It's the part in the middle that opens the "media option" that is missing. Is there a way to tell what the path is when the video is actually streaming


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