.bat file

[BonRouge]

I'm streaming 2 videos, on a loop, to the Internet. Everything's working fine.
My question is how to have the stream start more quickly. I couldn't find a good way to save the settings, so I figured a .bat file might be a good way. I set up the streaming as usual and copied the parameters that were showing.
Here's what I came up with by copying some code I found elsewhere on the forums:

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cd C:\Program Files\VideoLAN\VLC vlc [:sout=#transcode{vcodec=WMV1,vb=96,scale=1,acodec=mp3,ab=96,channels=1}:duplicate{dst=std{access=http,mux=asf,dst=:1234}}:sout-all] "C:\streams\big_vid_a.mpg" "C:\streams\big_vid_b.mpg"

This gives me this error:

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Unable to open '[:sout=#transcode{vcodec=WMV1,vb=96,scale=1,acodec=mp3,ab=96,channels=1}:duplicate{dst=std{access=http,mux=asf,dst=:1234}}'

The playlist has this as the first track:

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[:sout=#transcode{vcodec=WMV1,vb=96,scale=1,acodec=mp3,ab=96,channels=1}:duplicate{dst=std{access=http,mux=asf,dst=:1234}}

The video plays, but it plays locally too, which I don't need. I don't want to see the picture, I just need it to stream to the Internet.

I hope this is clear and I hope someone can point out what my problem is.

Thanks for any help.

[olegkirillov]

Remove the square bracket.

[BonRouge]

Thanks for the input.

I did what you said and got exactly the same results as before.

[olegkirillov]

Excuse me, I should be more detailed.

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vlc --sout=#transcode{vcodec=WMV1,vb=96,scale=1,acodec=mp3,ab=96,channels=1}:duplicate{dst=std{access=http,mux=asf,dst=:1234}} --sout-all "C:\streams\big_vid_a.mpg" "C:\streams\big_vid_b.mpg"

I suppose vb=96 is too low, though.

[BonRouge]

Thanks very much. That seems to do the job.

Maybe you could help me a little more... Are there any extra parameters I could add to close (or at least minimise) the CMD window and to minimise VLC?

Thanks again.

[olegkirillov]

Put "START /MIN vlc" in your .bat file

[BonRouge]

Thanks again.