python-vlc Stream from Capture Device with DirectShow

[genetica]

Good day,

I would like to stream a video from my capture device with directshow. When using the VLC Player I can go
> Media > Stream... > Capture Device:
Capture mode = DirectShow
Video device name = Datapath VisionSD4+1S 01
> Stream > Play
The player will then display the video feed.

I tried the basic:

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import vlc i = vlc.Instance() p = i.media_player_new() m = i.media_new('dshow://', 'dshow-vdev=Datapath VisionSD4+1S 01', 'dshow-adev=none', 'live-caching=300') p.set_media(m) p.play()

p.play() return 0 with an error:

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0005>>> a000000005a9e00] main input error: Your input can't be opened [00000000005a9e00] main input error: VLC is unable to open the MRL 'dshow://'.

I have tried it in various other ways but receive the same error. Any ideas?

How can I grab the video frames into an array for post processing?

Please assist?

[Jean-Baptiste Kempf]

Did you try adding the ":" before dshow-vdev?

[genetica]

Yes I have tried almost all configuration, such as using the add_option or '--' addition. Is there a way that I can check what is going wrong?

[Jean-Baptiste Kempf]

missing " " around the device name?

[genetica]

No, same error, I played around with the various combination as well. A note, when I create the instance I receive a

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Warning: option --plugin-path no longer exists.

[hakao]

Hello
I am trying to stream http audio,
When I use play() it also plays captured audio from my speakers.
There is an option in windows VLCPlayer aplication, "stream" instead of "play". Is there any at python?

This is my code:

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import vlc #define VLC instance instance = vlc.Instance("--sout '#transcode{vcodec=none,acodec=mp3,ab=128,channels=2,samplerate=44100}:std{access=http,mux=mp3,dst=:8080}' :no-sout-all :sout-keep") #Define VLC media transcoder = instance.media_player_new() media=instance.media_new('dshow://','dshow-vdev=None' ,'dshow-adev=', 'live-caching=30') #Set player media transcoder.set_media(media) #Play the media transcoder.play() while 1: pass